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4x^2-20x+25=180
We move all terms to the left:
4x^2-20x+25-(180)=0
We add all the numbers together, and all the variables
4x^2-20x-155=0
a = 4; b = -20; c = -155;
Δ = b2-4ac
Δ = -202-4·4·(-155)
Δ = 2880
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{2880}=\sqrt{576*5}=\sqrt{576}*\sqrt{5}=24\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-24\sqrt{5}}{2*4}=\frac{20-24\sqrt{5}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+24\sqrt{5}}{2*4}=\frac{20+24\sqrt{5}}{8} $
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